Factors of $8 x^{3} + 27 y^{3}$ are:

(x + 2) (x^{2} - 2 x + 4)

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(3 x + 4) (a x^{2} - 12 x + 16)

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(2 x + 3 y) (4 x^{2} - 6 x y + 9 y^{2})

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(x - 1) (x^{2} + 4 x + 7)

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Solution

The correct option is C $(2 x + 3 y) (4 x^{2} - 6 x y + 9 y^{2})$
$8 x^{3} + 27 y^{3} = (2 x)^{3} + (3 y)^{3}$
$= (2 x + 3 y) (4 x^{2} - 6 x y + 9 y^{2})$

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