Factors of $a^{4} - 2 a^{2} b^{2} + b^{4}$ are

(a + b)^{2}

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(a^{2} + b^{2} + 2 a b)

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(a^{2} + b^{2} - 2 a b)

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(a - b)

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Solution

The correct options are
A $(a + b)^{2}$
B $(a^{2} + b^{2} + 2 a b)$
C $(a^{2} + b^{2} - 2 a b)$
D $(a - b)$
$a^{4} - 2 a^{2} b^{2} + b^{4}$
$= (a^{2})^{2} - 2 a^{2} b^{2} + (b^{2})^{2}$
$= (a^{2} - b^{2})^{2}$
$= (a + b)^{2} (a - b)^{2}$

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Similar questions

a^{2} - b^{2} = (a + b) (a - b)

. Then factors of

1 + 2 a b - (a^{2} + b^{2})

are

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

a^{2} - b^{2} = (a + b) (a - b)

then factor of

1 + 2 a b - (a^{2} + b^{2})

are

Q. Factorize:
9 − a² + 2ab − b²

Q. Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

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Factors of a4−2a2b2+b4 are

The correct options are A (a+b)2 B (a2+b2+2ab) C (a2+b2−2ab) D (a−b) a4−2a2b2+b4=(a2)2−2a2b2+(b2)2=(a2−b2)2=(a+b)2(a−b)2

Factors of $a^{4} - 2 a^{2} b^{2} + b^{4}$ are

The correct options are
A $(a + b)^{2}$
B $(a^{2} + b^{2} + 2 a b)$
C $(a^{2} + b^{2} - 2 a b)$
D $(a - b)$
$a^{4} - 2 a^{2} b^{2} + b^{4}$
$= (a^{2})^{2} - 2 a^{2} b^{2} + (b^{2})^{2}$
$= (a^{2} - b^{2})^{2}$
$= (a + b)^{2} (a - b)^{2}$