Factors of $a^{2} - 8 a + 12$ are

(a - 6) (a - 2)

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(a + 6) (a - 2)

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(a - 6) (a + 2)

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(a - 4) (a - 3)

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Solution

The correct option is A $(a - 6) (a - 2)$
$a^{2} - 8 a + 12$
We need to split $12$ , such that the sum of two obtained integers is $8$ .
$∴ 6 \times 2 = 12$ and $6 + 2 = 8$

$∴ a^{2} - 8 a + 12$
$= a^{2} - 6 a - 2 a + 12$
$= a (a - 6) - 2 (a - 6)$
$= (a - 6) (a - 2)$

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