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Question

Factors of (pq)3+(qr)3+(rp)3 are:

A
pq(r+p)+qr(p+q)
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B
3(p-q)(q-r)(r-p)
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C
3(pq)(qr)(rp)
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D
3(p+q)(q+r)(r+p)
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Solution

The correct option is B 3(p-q)(q-r)(r-p)
Let a=pq,b=qr and c=rp
We see that
a+b+c=(pq)+(qr)+(rp)=0
Now, we know that a3+b3+c33abc=(a+b+c)(a2+b2+c2abbcca)
if (a+b+c)=0 then a3+b3+c33abc=0
a3+b3+c3=3abc
(pq)3+(qr)3+(rp)3
=3(pq)(qr)(rp)

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