Factors of $(x^{2} - 2 x y + y^{2}) - z^{2}$ are

(x - y - z)

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(x - y + z)

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1

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(x + y - z)

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Solution

The correct options are
A $(x - y - z)$
C $1$
D $(x - y + z)$
$(x^{2} - 2 x y + y^{2}) - z^{2}$
$= (x - y)^{2} - z^{2}$
$= (x - y + z) (x - y - z)$
$= 1 \times (x - y + z) (x - y - z)$

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