Factors of $x^{2} + 4 x - 21$ are:

(x - 3) (x - 7)

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(x + 7) (x - 3)

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(x + 3) (x + 7)

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None of these

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Solution

The correct option is B $(x + 7) (x - 3)$
$x^{2} + 4 x - 21 = x^{2} + 7 x - 3 x - 21$
$x (x + 7) - 3 (x + 7) = (x + 7) (x - 3)$

Suggest Corrections

Similar questions

$(x^{2} - 4 x - 21)$ =?

(a) $(x - 7) (x - 3)$

(b) $(x + 7) (x - 3)$

(d) None of these

The factors of x⁴ + x² + 25 are

(a) (x² + 3x + 5) (x² − 3x + 5)

(b) (x²+ 3x + 5) (x² + 3x − 5)

(c) (x² + x +5) (x² − x + 5)

(d) none of these

Factorize: $x^{2} - 10 x + 21$ .

Check whether $7 + 3 x$ is a factor of $3 x^{3} + 7 x$ . [2 MARKS]

x^{3} + 3 x^{2} + 3 x - 7

x^{3} - 3 x^{2} + 3 x + 7

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