wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factors of x2+4x−21 are:

A
(x3)(x7)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(x+7)(x3)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(x+3)(x+7)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (x+7)(x3)
x2+4x21=x2+7x3x21
x(x+7)3(x+7)=(x+7)(x3)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation Using Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon