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Byju's Answer
Standard X
Mathematics
Factor of a Polynomial
Factors of ...
Question
Factors of
x
6
+
9
x
3
+
8
are:
A
(
x
−
2
)
(
x
2
+
2
x
+
4
)
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B
(
x
+
2
)
(
x
2
−
2
x
+
4
)
(
x
+
1
)
(
x
2
−
x
+
1
)
.
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C
(
x
−
1
)
(
x
2
−
2
x
+
4
)
(
x
+
1
)
(
x
2
−
x
+
1
)
.
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D
None of these
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Solution
The correct option is
B
(
x
+
2
)
(
x
2
−
2
x
+
4
)
(
x
+
1
)
(
x
2
−
x
+
1
)
.
x
6
+
9
x
3
+
8
=
x
6
+
8
x
3
+
x
3
+
8
=
x
3
(
x
3
+
8
)
+
1
(
x
3
+
8
)
=
(
x
3
+
8
)
(
x
3
+
1
)
=
(
x
3
+
2
3
)
(
x
3
+
1
3
)
=
(
x
+
2
)
(
x
2
−
2
x
+
4
)
(
x
+
1
)
(
x
2
−
x
+
1
)
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0
Similar questions
Q.
Factorise
2
x
7
−
128
x
Q.
lim
x
→
∞
(
x
+
1
2
x
+
1
)
x
2
equals
Q.
lim
x
→
a
(
x
+
1
2
x
+
1
)
x
2
=
Q.
The factorization of
x
3
+
1
is
Q.
If
(
sin
−
1
x
)
2
−
(
cos
−
1
x
)
2
=
a
;
0
<
x
<
1
,
a
≠
0
, then the value of
2
x
2
−
1
is:
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