Question

FairPlay Athletics club has six coaches, viz, $A,B,C,D,E$ and $F$. A panel of coaches comprising of three members has to be formed In how many of these panels will coach $C$ be excluded?

Answer 1

Given that we need to form the panel excluding $C.$ So, we now have only $5$ coaches to select from to from the $3$ coach panel.

$\Rightarrow$ Total combinations $={}^5{C}_3=10$

Hence, the answer is $10.$