Question

Question 113

Family photograph has length $14\frac{2}{5}$ cm and breadth $10\frac{2}{5}$ cm. It has border fo uniform width $2\frac{3}{5}$ cm. Find the area of farmed photograph.

Answer 1

Length of family photograph = $14\frac{2}{5}$ cm
= $\frac{(14\times 5)+2}{5}$ = $\frac{72}{5}$ cm

Breadth fo family photograph $=10\frac{2}{5}cm=\frac{(10\times 5)+2}{5}=\frac{52}{5}cm$
New length including border (from both sides)
$=\frac{72}{5}+(2\frac{3}{5}\times 2)=\frac{72}{5}+(\frac{13}{5}\times 2)$
New width including border (from both sides )
$=\frac{52}{5}+(2\frac{3}{5}\times 2)=\frac{52}{5}+\frac{26}{5}=\frac{52+26}{5}=\frac{78}{5}cm$
$\therefore$ Area of framed photograph = length $\times$Breadth
$=\frac{98}{5}\times \frac{78}{5}=\frac{7644}{25}$
$=305\frac{19}{25}c{m}^2$
Hence the area fo framed photograph is $305\frac{19}{25}c{m}^2$