Family photograph has length 24 isto 2 by 5 cm.and breadth 20 isto 2 by 5 cm.It has border of width with 8 isto 8 by 5 cm. Find the area of framed photograph ?

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Solution

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$L e n g t h o f p h o t o = 24 \frac{2}{5} c m = \frac{122}{5} c m B r e a d t h o f p h o t o = 20 \frac{2}{5} c m = \frac{102}{5} c m A d d i n g t h e b o r d e r t o b o t h l e n g t h a n d b r e a d t h o n b o t h s i d e s o f t h e p h o t o . B o r d e r = 8 \frac{8}{5} c m = \frac{48}{5} c m T w i c e o f b o r d e r = 2 \times \frac{48}{5} c m = \frac{96}{5} c m N e w l e n g t h o f p h o t o f r a m e = \frac{122}{5} + \frac{96}{5} = \frac{218}{5} c m N e w b r e a d t h o f p h o t o f r a m e = \frac{102}{5} + \frac{96}{5} = \frac{198}{5} c m A r e a o f p h o t o = L e n g t h \times B r e a d t h = \frac{218}{5} \times \frac{198}{5} = \frac{43164}{5} c m^{2} = 8632.8 c m^{2}$
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