Question

Faraday's law of electromagnetic induction is given by, $$\oint \overrightarrow{E}.d\overrightarrow{l}=-\frac{d{\varphi }_B}{dt}$$Then -

• A. The electric field $\overrightarrow{E}$, in the given equation, is conservative.
• B. The electric field $\overrightarrow{E}$, in the given equation, is non-conservative.
• C. Work done by the force due to the electric field $\overrightarrow{E}$, in the given equation, in moving a charge over a closed path is zero.
• D. None of these

Answer 1

The correct option is B The electric field $\overrightarrow{E}$, in the given equation, is non-conservative.

Faraday's Law of Electromagnetic Induction,

$\oint \overrightarrow{E}.d\overrightarrow{l}=-\frac{d{\varphi }_B}{dt}$

Work done by the force due to the electric field $\overrightarrow{E}$, in the above equation, in moving a charge over a closed path can not be zero.

Therefore, the electric field $\overrightarrow{E}$ is non-conservative in nature.

Hence, option $\left(B\right)$ is the correct answer.