Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
The correct option is A: 2 times
Let Ronit's present age be x years. Then, father's present age =(x+3x) years =4x years. [His father is 3 times more that ronit's age so, x+3x will be his age now ]
After 8 years, Ronit,s Age =x+8
His father's age =(4x+8)
According to the question, we have
Further 8 years will means 16 years from the current age.
After 16 years from present, the ratio of their ages will be
His father's ageRonit' age=(4x+16)(x+16)=4×8+168+16=4824=2.
∴ His father =2× Ronit age
Hence, his father will be 2 times Ronit's present age after 16 years from now.