Question

# Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

A

2 times

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B

212 times

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C

234 times

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D

3 times

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Solution

## The correct option is A: 2 timesLet Ronit's present age be x years. Then, father's present age =(x+3x) years =4x years. [His father is 3 times more that ronit's age so, x+3x will be his age now ]After 8 years, Ronit,s Age =x+8His father's age =(4x+8)According to the question, we have ∴(4x+8)=52(x+8) ⇒8x+16=5x+40 ⇒3x=24 ⇒x=8.Further 8 years will means 16 years from the current age.After 16 years from present, the ratio of their ages will be His father's ageRonit' age=(4x+16)(x+16)=4×8+168+16=4824=2.∴ His father =2× Ronit ageHence, his father will be 2 times Ronit's present age after 16 years from now.

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