Question

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

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Solution

The correct option is **A:** 2 times

Let Ronit's present age be x years. Then, father's present age =(x+3x) years =4x years. [His father is 3 times more that ronit's age so, x+3x will be his age now ]

After 8 years, Ronit,s Age =x+8

His father's age =(4x+8)

According to the question, we have

∴(4x+8)=52(x+8)

⇒8x+16=5x+40

⇒3x=24

⇒x=8.

Further 8 years will means 16 years from the current age.

After 16 years from present, the ratio of their ages will be

His father's ageRonit' age=(4x+16)(x+16)=4×8+168+16=4824=2.

∴ His father =2× Ronit age

Hence, his father will be 2 times Ronit's present age after 16 years from now.

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