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Question

Father's age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

A
Father's age =75 years
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B
Father's age =45 years
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C
Father's age =66 years
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D
Father's age =88 years
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Solution

The correct option is B Father's age =45 years

Let the age of father =x years
The sum of the age of 2 children =y years
According to the first condition
x=3y.....eq1
After 5 years
Father's age =x+5
The sum of ages of his two children =y+10

According to the second condition
x+5=2(y+10)x+5=2y+20
x2y=15....eq2
Put the value of x from eq1
3y2y=15y=15
Put y=15 in eq1
x=3×15x=45

Hence, father age =45 years


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