Fe2- - 2e- - Fe- E-0-44 V Cu2- - 2e- - Cu- E-0-34 VThe E- of Fe - Cu2- Fe2 -Cu is and thus- reaction is spontaneous-nonspontaneous-

The correct option is A 0.78 V and spontaneous Fe^2+ + 2e^ → Fe ; E^∘= 0.44 V (1) Cu^2+ + 2e^ → Cu ; #160; E^∘=+0.34 V (2)Inver ...

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Oxides of Xenon

Fe2+ + 2e- → ...

Question

$F e^{2 +} + 2 e^{-} \to F e$ ; $E^{\circ} = - 0.44 V$
$C u^{2 +} + 2 e^{-} \to C u$ ; $E^{\circ} = + 0.34 V$
The $E^{\circ}$ of $F e + C u^{2 +} ⇋ F e^{2} + C u$ is _______ and thus, reaction is spontaneous/nonspontaneous.

0.78 V

and spontaneous

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0.78 V

and nonspontaneous

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- 0.78 V

and spontaneous

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- 0.78 V

and nonspontaneous

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Similar questions

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s), Δ H^{0} = - 219 k J, Δ S^{0} = - 21 J K^{- 1}

Δ G^{o}

C u^{2 +} + F e \to F e^{2 +} + C u

E_{C u^{2 +} | C u}^{o} = + 0.34

E_{F e^{2 +} | F e}^{o} = - 0.44

E^{\circ}

F e / {F e}^{2 +}

E^{\circ}

C u / {C u}^{2 +}

F e \to F e^{2 +} + 2 e^{-} (+ 0.44

)

P b \to P b^{2 +} + 2 e^{-} (+ 0.13

)

C u \to C u^{2 +} + 2 e^{-} (- 0.34

)

2 A g^{+} + 2 e^{-} \to 2 A g^{0} (+ 0.80

)

A u^{+} (a q) + e^{-} \to A u (s); E^{0} = 1.69 V

C u^{2 +} (a q) + 2 e^{-} \to C u (s); E^{0} = 0.34 V

P b^{2 +} (a q) + 2 e^{-} \to P b (s); E^{0} = - 0.13 V

F e^{2 +} (a q) + 2 e^{-} \to F e (s); E^{0} = - 0.44 V

C a^{2 +} (a q) + 2 e^{-} \to C a (s); E^{0} = - 2.87 V

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