${F e}^{2 +}$ ion is distinguished from ${F e}^{3 +}$ ion by

B a {C l}_{2}

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K C N

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N a N O_{3}

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N H_{4} S C N

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Solution

The correct option is B $N H_{4} S C N$
The chemical compound to be distinguished should gives different colouration with reagent.
${F e}^{2 +} + N H_{4} S C N ⟶$ No change in colour
${F e}^{3 +} + N H_{4} S C N ⟶$ Red colouration
Therefore, $N H_{4} S C N$ is used to distinguish between ${F e}^{2 +}$ and ${F e}^{3 +}$ .

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