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Variable Oxidation States

Fe3+compounds...

Question

$F e^{3 +}$ compounds are more stable than $F e^{2 +}$ compounds because:

F e^{3 +}

has smaller size than

F e^{2 +}

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F e^{3 +}

has

3 d^{5}

configuration (half-filled)

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F e^{3 +}

has higher oxidation state

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F e^{3 +}

is paramagnetic in nature

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Solution

The correct option is A $F e^{3 +}$ has $3 d^{5}$ configuration (half-filled)
Stability depends on the electronic configurations of respective ions/elements.
$F e^{+ 3}$ has an electronic configuration of $[A r] 3 d^{5} 4 s^{0}$ and
$F e^{+ 2}$ has an electronic configuration of $[A r] 3 d^{6} 4 s^{0}$ , $F e^{+ 3}$ being half filled is more stable than $F e^{+ 2}$ which is incompletely filled.

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F e | F e^{2 +} | | F e^{3 +}, F e^{2 +} | P t

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E_{F e^{3 +} | F e^{2 +}}^{0} = 0.77 V

E^{\circ}

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O i s 1.23 V F e^{3 +} + e^{-} \to F e^{2 +} i s 0.77 V

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