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Byju's Answer
Standard XII
Chemistry
Variable Oxidation States
Fe3+compounds...
Question
F
e
3
+
compounds are more stable than
F
e
2
+
compounds because:
A
F
e
3
+
has smaller size than
F
e
2
+
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B
F
e
3
+
has
3
d
5
configuration (half-filled)
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C
F
e
3
+
has higher oxidation state
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D
F
e
3
+
is paramagnetic in nature
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Solution
The correct option is
A
F
e
3
+
has
3
d
5
configuration (half-filled)
Stability depends on the electronic configurations of respective ions/elements.
F
e
+
3
has an electronic configuration of
[
A
r
]
3
d
5
4
s
0
and
F
e
+
2
has an electronic configuration of
[
A
r
]
3
d
6
4
s
0
,
F
e
+
3
being half filled is more stable than
F
e
+
2
which is incompletely filled.
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0
Similar questions
Q.
Element
F
e
has two oxidation states
F
e
2
+
&
F
e
3
+
, the correct order of radii of these ions will be:
Q.
Assertion :
C
u
+
is less stable than
C
u
2
+
but
F
e
3
+
is more stable than
F
e
2
+
. Reason: Half filled and completely filled subshells are more stable.
Q.
Which of the following statements are correct for the given electrochemical cells?
(I)
F
e
|
F
e
2
+
|
|
F
e
3
+
|
F
e
(II)
F
e
|
F
e
2
+
|
|
F
e
3
+
,
F
e
2
+
|
P
t
(III)
F
e
|
F
e
3
+
|
|
F
e
3
+
,
F
e
2
+
|
P
t
Q.
Calculate the reduction potential at
25
o
C for
F
e
3
+
|
F
e
2
+
electrode, if the concentration of
F
e
2
+
ion is
10
times higher than
F
e
3
+
ion.
[Given
E
0
F
e
3
+
|
F
e
2
+
=
0.77
V
].
Q.
E
∘
for the half cells :
M
n
O
2
+
4
H
+
+
2
e
−
→
M
n
2
+
+
2
H
2
O
i
s
1.23
V
F
e
3
+
+
e
−
→
F
e
2
+
i
s
0.77
V
Which of the following statements is true?
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