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Hydrogen Peroxide

Fe3+ is reduc...

Question

$F e^{3 +}$ is reduced to $F e^{2 +}$ by using:

A

H_{2} O_{2}

is presence of

N a O H

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B

N a_{2} O_{2}

in water

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C

H_{2} O_{2}

in presence of

H_{2} S O_{4}

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D

N a_{2} O_{2}

in presence of

H_{2} S O_{4}

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Solution

The correct options are
A $N a_{2} O_{2}$ in water
D $H_{2} O_{2}$ is presence of $N a O H$
In basic medium $H_{2} O_{2}$ acts as reducing agent.
$N a_{2} O_{2} + 2 H_{2} O \to 2 N a O H + H_{2} O_{2}$
$2 F e^{3 +} + H_{2} O_{2} + 2 O H^{-} \to 2 F e^{2 +} + 2 H_{2} O + O_{2}$ .

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