$F e^{3 +}$ oxidises $N H_{2} O H$ to give:

N O_{2}

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N_{2} O

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N_{2}

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N O

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Solution

The correct option is B $N_{2} O$
Reaction is:
$4 F e^{3 +} (a q) + 2 N H_{2} O H (a q) \to 4 F e^{2 +} (a q) + N_{2} O (g) + H_{2} O (l) + 4 H^{+} (a q)$

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Similar questions

F e^{3 +}

N H_{2} O H

N_{2} O, N O, N O_{2}, O_{2}, N O_{2}^{+}, N O^{+}, C O^{+}

H N O_{3}

\to Z n (N O_{3})_{2} + X + H_{2} O

H N O_{3}

\to Z n (N O_{3})_{2} + Y + H_{2} O

F e^{2 +} + 2 H^{+} + N O_{3}^{-} \to F e^{3 +} + N O_{2} + H_{2} O

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