$F e^{3 +}$ oxidises $N H_{2} O H$ to :

N O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2} O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $N_{2} O$
Reaction is:
$4 F e^{3 +} (a q) + 2 N H_{2} O H (a q) \to 4 F e^{2 +} (a q) + N_{2} O (g) + H_{2} O (l) + 4 H^{+} (a q)$

Suggest Corrections

Similar questions

F e^{3 +}

N H_{2} O H

N_{2} O, C O_{2}, {C N}_{2}^{2 -}, N_{3}^{-}, N H_{2} O H, N_{3} H

F e^{2 +} + 2 H^{+} + N O_{3}^{-} \to F e^{3 +} + N O_{2} + H_{2} O

S O_{2}, C O_{2}, N_{2} O, O F_{2}, {I C l_{2}}^{-}, {I_{3}}^{-}, N O_{2}, {N O_{2}}^{-}, {N O_{2}}^{+}, {B F_{2}}^{-}, B e C l_{2}, {N_{3}}^{-}, H C N .

Z n + c o n c . H N O_{3} (h o t) \to Z n (N O_{3})_{2} + X + H_{2} O

Z n + d i l . H N O_{3} (cold) \to Z n (N O_{3})_{2} + Y + H_{2} O

Join BYJU'S Learning Program