$F e {C l}_{3}$ solution added to $K_{4} [{F e (C N)}_{6}]$ gives A while with $K S C N$ gives B. A and B respectively are:

{F e}_{3} {[{F e (C N)}_{6}]}_{2}, F e (C N S)_{3}

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{F e}_{4} {[{F e (C N)}_{6}]}_{3}, K F e (C N S)_{3}

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{F e}_{4} {[{F e (C N)}_{6}]}_{3}, K_{3} [{F e (C N S)}_{6}]

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{F e}_{4} {[{F e (C N)}_{6}]}_{3}, K_{3} [{F e (S C N)}_{6}]

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Solution

The correct option is D ${F e}_{4} {[{F e (C N)}_{6}]}_{3}, K_{3} [{F e (S C N)}_{6}]$
$F e {C l}_{3}$ reacts with potassium ferrocyanide to form
$4 F e {C l}_{3} + 3 K_{4} [{F e (C N)}_{6}] \to {F e}_{4} {[{F e (C N)}_{6}]}_{3} A, P u r s s i a n b l u e + 12 K C l$
$F e {C l}_{3}$ reacts with KSCN to form deep red colour complex of $K_{3} [{F e (S C N)}_{6}]$
$F e {C l}_{3} + 3 K S C N \to K_{3} [{F e (S C N)}_{6}] B, d e e p r e d c o l o u r + 3 K C l$

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