Question

$\left[Fe\right(CN{)}_6{]}^{3\ominus }$ has a magnetic moment of 1.73 BM. Thus hybridization of Fe is

• A. $d^{2}s{p}^3$
• B. $s{p}^3{d}^2$
• C. $ds{p}^2$
• D. $s{p}^3$

Answer 1

The correct option is A $d^{2}s{p}^3$

As per VBT, the complex is $d^{2}s{p}^3$ hybridized. Use formula : $\mu =\sqrt{n(n+2)}$