FeCr2O4 chromite is converted to Cr by following steps-Chromite Na2CrO4Cr2O3 Cr I-II and III are-

$\begin{matrix} Column I & Column 2 & Column 3 Equation of AB & Area of Δ O A B (I) & Centroid Δ O A B is (1, 2) & (i) & 2 x + y = 2 & (P) & 6 sq. units (II) & Circumcenter of Δ O A B is (1, 2) & (ii) & 3 x + 4 y = 12 & (Q) & 9 sq. units (III) & Distance of the orthocentre of Δ O A B & (iii) & 2 x + y = 6 & (R) & 1 sq. units From A and B is 1 and 2 respectively (IV) & Incenter of Δ O A B is (1, 1) & (iv) & 2 x + y = 4 & (S) & 4 sq. units \end{matrix}$

Which of the following is correct combination?

Q. Predict the products of the following reactions:

(i) C H_{3} - C | C H_{3} = O H C N - -- \to ?

(i i) C_{6} H_{5} - C H_{2} - C H_{3} (a) K M n O_{4} / K O H - ---------- \to (b) H^{+} ?

(i i i) C H_{3} C O O H N H_{3} / Δ - --- \to ?

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FeCr2O4 (chromite) is converted to Cr by following steps:ChromiteI→Na2CrO4II−→Cr2O3III−−→CrI,II and III are:

The correct option is D I−Na2CO3/air,Δ; II−C,Δ; III−Al,ΔChromite is converted into sodium chromate and then to Cr by given reaction:FeCr2O4Na2CO3/air,Δ−−−−−−−−−→Na2CrO4C→Cr2O3Al,Δ−−−→CrHence, option B is correct.

$F e {C r}_{2} O_{4}$ (chromite) is converted to $C r$ by following steps:
Chromite $I \to {N a}_{2} C r O_{4} I I - \to {C r}_{2} O_{3} I I I - - \to C r$
$I, I I$ and $I I I$ are: