$F e + C u S O_{4} \to$ _ + _

F e S O_{2}, C u_{2}

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F e S O_{4}, C u

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F e_{2} S O_{4}, C u

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None of above

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Solution

The correct option is B $F e S O_{4}, C u$
Copper(II) sulphate is blue, iron sulphate is colourless. During the reaction the blue solution loses its colour and the iron metal is seen to turn pink-brown as the displaced copper becomes deposited on it. Iron is more reactive than copper and hence it displaces copper.
$F e + C u S O_{4} \to F e S O_{4} + C u$

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Similar questions

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{o} C

E^{0} [F e \to F e^{2 +}) = 0.44 V

E^{0} (C u \to C u^{2 +}) = - 0.337 V

F e + {C u S O}_{4} ⇌ {F e S O}_{4} + C u

E_{F e / F e}^{o} = 0.44 V; E_{C u / {C u}^{2 +}}^{o} = - 0.337 V

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{0}

E^{0} (F e / F e^{2 +}) = 0.44 V, E^{0} (C u / C u^{2 +}) = - 0.337 V

F e + C u S O_{4} ⟶ F e S O_{4} + C u

25^{o}

E_{(F e / F e^{2 +})}^{0} = 0.44 V

E_{(C u / C u^{2 +})}^{0} = - 0.337 V

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