The correct option is B paramagnetic in nature
In given complex, the oxidation state of Fe is +2, so, its configuration is d6.
As CFSE is less than pairing energy according to given values :-
CFSE=10,400 cm−1
P.E=17,600 cm−1
It means weak field or high spin complex.
Thus, there is presence of unpaired electrons and hence it is paramagnetic in nature.
Its configuration is t42g e2g
Hence, correct answer is option B.