$F e I_{3}$ does not exist because:

of large size

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{F e}^{3 +}

oxidises

I^{-}

I_{2}

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of two lattice energy

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iodine is not highly electronegative enough to oxidise

F e

{F e}^{3 +}

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Solution

The correct option is B ${F e}^{3 +}$ oxidises $I^{-}$ to $I_{2}$

$F e I_{3}$ does not exist because ${F e}^{3 +}$ oxidises $I^{-}$ to $I_{2}$

Hence option B is correct.

Suggest Corrections

Similar questions

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

F e^{3 +}

oxidises

N H_{2} O H

to :

F e^{3 +}

oxidises

N H_{2} O H

to give:

Why Fe²⁺radialy oxidises to Fe³⁺??

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FeI3 does not exist because:

The correct option is B Fe3+ oxidises I− to I2 FeI3 does not exist because Fe3+ oxidises I− to I2 Hence option B is correct.

$F e I_{3}$ does not exist because:

The correct option is B ${F e}^{3 +}$ oxidises $I^{-}$ to $I_{2}$

$F e I_{3}$ does not exist because ${F e}^{3 +}$ oxidises $I^{-}$ to $I_{2}$

Hence option B is correct.