Question

$F{e}^{+}$ ions are accelerated through a potential difference of 500 V and are injected normally into a homogeneous magnetic field B of strength 20.0 mT. Find the radius of the circular paths followed by the isotopes with mass numbers 57 and 58. Take the mass of an ion $=A(1.6\times {10}^{-27})$ kg where A is the mass number.

Answer 1

$V=500V,$

$B=20mT=(20\times {10}^{-3})T$

Using $v^2=2ad$

Hence $r_1=11.9\times {10}^{-2}m=119cm$

$r_2=1.20m=120cm$