$F e + S \to F e S$ . In the above reaction, how many equation of electrons are lost by the iron atom and how it acts?

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Solution

Two electrons are lost by iron and it works as reducing agent.
$F e \to F e^{2 +} + 2 e^{-}$
$S + 2 e^{-} \to S^{2 -}$
$F e^{2 +} + S 2 - \to F e S$

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An ammeter reading shows a current of 0.50 A running through the iron hull. How many grams of $F e (s)$ are lost in 1.0 hour?

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