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Brown Ring Test

FeSO4 is used...

Question

$F e {S O}_{4}$ is used in brown ring test for nitrates and nitrites In this test, a freshly prepared $F e {S O}_{4}$ solution solution is mixed with solution containing ${N O}_{2}^{-}$ and ${N O}_{3}^{-}$ and the conc, $H_{2} {S O}_{4}$ is run down the side of the test tube. If the mixture gets hot or is shaken,
$(I)$ the brown colour disappear $(I I)$ $N O$ is evolved
$(I I I)$ a yellow solution of ${F e}_{2} {({S O}_{4})}_{3}$

I, I I, I I I

correct

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I, I I I

correct

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I I, I I I

correct

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only

I

correct

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Solution

The correct option is A $I, I I, I I I$ correct
The brown ring is formed due to presence of brown coloured double compound nitroso ferrous sulphate $F e (N O) S O_{4}$
$F e S O_{4} + N O f r o m n i t r a t e s \to F e (N O) S O_{4} b r o w n r i n g$
When the mixture is shaken or if it gets hot, the complex breaks to form a yellow solution of ${F e}_{2} {({S O}_{4})}_{3}$ .
Hence, the brown colour disappears and NO is evolved.

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Similar questions

{[F e {(H_{2} O)}_{5} N O]}^{2 +}

F e {S O}_{4}

{N O}_{3}^{-}

H_{2} {S O}_{4}

F e S O_{4}

[F e (H_{2} O)_{5} N O]^{2 +}

F e S O_{4}

N O_{3}^{-}

H_{2} S O_{4}

Choose the correct answer :

(a) The nitrate salt which does not give a mixture of $N O_{2}$ and $O_{2}$ on heating is :

(i) $A g N O_{3}$ , (ii) $K N O_{3}$ ,

(iii) $C u (N O_{3})_{3}$ , (iv) $Z n (N O_{3})_{2}$ .

(b) The chemical used in the brown ring test is :

(i) $C u S O_{4}$ , (ii) $F e S O_{4}$

(iii) $F e_{2} (S O_{4})_{3}$ (iv) $Z n S O_{4}$ .

(i) NO, (ii) $N_{2} O,$

(iii) $N O_{2}$ (iv) $N_{2} O_{5}$ .

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