Byju's Answer
Standard VII
Chemistry
Equilibrium Constant from Nernst Equation
. Fe3+(aq) + ...
Question
. Fe3+(aq) + e– → Fe2+(aq), E° = +0.77 V Cl2(g) + 2e– → 2Cl–(aq), E° = +1.36 V Write the reaction which could be feasible using above half cells.
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Q.
Choose the correct option(s) for the given half cell reactions:
F
2
(
g
)
+
2
e
−
→
2
F
−
(
a
q
)
;
E
0
=
2.87
V
C
l
2
(
g
)
+
2
e
−
→
2
C
l
−
(
a
q
)
;
E
0
=
1.36
V
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
;
E
0
=
0.77
V
Q.
What will be the
E
0
value for the given half cell reaction?
F
e
3
+
(
a
q
)
+
3
e
−
→
F
e
(
s
)
Given:
E
0
value for the half cell reaction,
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
;
E
0
=
0.77
V
F
e
2
+
(
a
q
)
+
2
e
−
→
F
e
(
s
)
;
E
0
=
−
0.44
V
Q.
Which of the following statements is true for the following half cell reactions?
F
2
(
g
)
+
2
e
−
→
2
F
−
(
a
q
)
;
E
0
=
2.87
V
C
l
2
(
g
)
+
2
e
−
→
C
l
−
(
a
q
)
;
E
0
=
1.36
V
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
;
E
0
=
0.77
V
Q.
Which of the following statement(s) is/are true for the following half cell reactions?
F
2
(
g
)
+
2
e
−
→
2
F
−
(
a
q
)
;
E
0
=
2.87
V
C
l
2
(
g
)
+
2
e
−
→
C
l
−
(
a
q
)
;
E
0
=
1.36
V
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
;
E
0
=
0.77
V
Q.
Choose the correct statement among the following for the given half cell reaction:
F
2
(
g
)
+
2
e
−
→
2
F
−
(
a
q
)
;
E
0
=
2.87
V
C
l
2
(
g
)
+
2
e
−
→
C
l
−
(
a
q
)
;
E
0
=
1.36
V
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
;
E
0
=
0.77
V
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