Question

$FeC{l}_3\cdot 6H_{2}O$ is actually:

• A. $\left[Fe\right(H_{2}O{)}_6]C{l}_3$
• B. $\left[Fe\right(H_{2}O{)}_{5}Cl]Cl\cdot H_{2}O$
• C. $\left[Fe\right(H_{2}O{)}_{4}C{l}_2]Cl\cdot 2H_{2}O$
• D. $\left[Fe\right(H_{2}O{)}_{3}C{l}_3]\cdot 3H_{2}O$

Answer 1

The correct option is C $\left[Fe\right(H_{2}O{)}_{4}C{l}_2]Cl\cdot 2H_{2}O$

$FeC{l}_3\cdot 6H_{2}O$ is actually $\left[Fe\right(H_{2}O{)}_{4}C{l}_2]Cl\cdot 2H_{2}O$.
Out of three chlorine atoms, two are present in the coordination sphere and one is present in the ionization sphere.
Out of six water atoms, four are present in the coordination sphere and two are present in the ionization sphere.