$F e C l_{3}$ reacts with ammonium hydroxide to give a reddish brown precipitate of metallic hydroxide which is insoluble in excess of $N H_{4} O H$ . Name this precipitate.

Fe(OH)₂

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Fe(OH)₃

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Fe(OH)₄

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NaOH

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Solution

The correct option is B
Fe(OH)₃

FeCl₃ reacts with ammonium hydroxide to give ammonium chloride along with reddish brown precipitate of Fe(OH)₃ which is insoluble in excess of NH₄OH.

$F e C I_{3} + 3 N H_{4} O H \to 3 N H_{4} C I + F e (O H)_{3} ↓$

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When lead nitrate reacts with ammonium hydroxide, a chalky white precipitate is formed. The precipitate formed is insoluble in excess of ammonium hydroxide. Name this precipitate.

Q. (a) Sodium hydroxide solution is added to solution A. A white precipitate is formed which is insoluble in excess sodium hydroxide solution. Name the metal ion present in solution A.
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Q. Three cations

A, B, C

are allowed to react with ammonium hydroxide solution.

A

and

B

produce a dirty green precipitate and a reddish brown precipitate respectively, both of which do not dissolve on further addition of

{N H}_{4} O H

C

gives pale blue colour precipitate with less amount of ammonium hydroxide and on further addition of

{N H}_{4} O H

, precipitate becomes soluble and deep blue colour solution is formed:

Zinc nitrate reacts with ammonium hydroxide to give a white gelatinous precipitate of X which is soluble in excess of ammonium hydroxide. What is X?

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FeCl3 reacts with ammonium hydroxide to give a reddish brown precipitate of metallic hydroxide which is insoluble in excess of NH4OH. Name this precipitate.

The correct option is B Fe(OH)3 FeCl3 reacts with ammonium hydroxide to give ammonium chloride along with reddish brown precipitate of Fe(OH)3 which is insoluble in excess of NH4OH. FeCI3+3NH4OH→3NH4CI+Fe(OH)3↓

$F e C l_{3}$ reacts with ammonium hydroxide to give a reddish brown precipitate of metallic hydroxide which is insoluble in excess of $N H_{4} O H$ . Name this precipitate.

The correct option is B
Fe(OH)₃

FeCl₃ reacts with ammonium hydroxide to give ammonium chloride along with reddish brown precipitate of Fe(OH)₃ which is insoluble in excess of NH₄OH.

$F e C I_{3} + 3 N H_{4} O H \to 3 N H_{4} C I + F e (O H)_{3} ↓$