Ferric ion forms a prussian blue colored ppt. due to the formation of:

K_{4} [F e {(C N)}_{6}]

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F e_{4} {[F e {(C N)}_{6}]}_{3}

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K M n O_{4}

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F e {(O H)}_{3}

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Solution

The correct option is B $F e_{4} {[F e {(C N)}_{6}]}_{3}$
Ferric ion forms a prussian blue colored ppt. due to the formation of $F e_{4} {[F e {(C N)}_{6}]}_{3}$ .
$\begin{matrix} 2 F e_{2} {(S O_{4})}_{3} + 3 K_{4} [F e {(C N)}_{6}] ⟶ & F e_{4} {[F e {(C N)}_{6}]}_{3} & + 6 K_{2} S O_{4} . P r u s s i a n b l u e \end{matrix}$

Option (B) is correct.

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Similar questions

K_{4} [F e (C N)_{6}]

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na₄[Fe(CN)₆] (b) Fe₄[Fe(CN)₆]₃ (c) Fe₂[Fe(CN)₆] (d) Fe₃[Fe(CN)₆]₄

K_{4} [F e (C N)_{6}]

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