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Colours in Coordination Compounds

Ferric ion fo...

Question

Ferric ion forms a Prussian blue coloured precipitate with $K_{4} [F e (C N)_{6}]$ due to the formation of :

K_{3} [F e (C N)_{6}]

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F e_{4} [F e (C N)_{6}]_{3}

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F e (O H)_{3}

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K F e [F e (C N)_{6}]

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Solution

The correct option is B $F e_{4} [F e (C N)_{6}]_{3}$
$F e^{3 +} + K_{4} [F e^{2 +} (C N)_{6}] \to F e_{4} [F e (C N)_{6}]_{3}$ Prussian blue

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Similar questions

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na₄[Fe(CN)₆] (b) Fe₄[Fe(CN)₆]₃ (c) Fe₂[Fe(CN)₆] (d) Fe₃[Fe(CN)₆]₄

F e (O H)_{3}

{F e}^{2 +}

K_{3} [{F e (C N)}_{6}]

{F e}^{3 +}

K_{4} [{F e (C N)}_{6}]

F e C l_{3} (a q)

K_{4} [F e (C N)_{6}]

F e C l_{3}

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F e_{4} [F e (C N)_{6}]

{N H}_{2} - {N H}_{2}

{F e}_{4} {[F e ({C N}_{6})]}_{3}

F e {S o}_{4}, F e {C I}_{3}

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