Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

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Solution

Let the number of oxide (O²⁻) ions be x.

So, number of octahedral voids = x

It is given that two out of every three octahedral holes are occupied by ferric ions.

So, number of ferric (Fe³⁺) ions

Therefore, ratio of the number of Fe³⁺ ions to the number of O²⁻ ions,
Fe³⁺ : O²⁻

= 2 : 3

Hence, the formula of the ferric oxide is Fe₂O₃.

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