Ferric oxide crystallizes in a hexagonal close packed structure of oxide,O^2- ions. Two out of every three octohedral holes are occupied by iron ions.what is the formula of ferric oxide?

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Solution

Suppose the number of oxide (O2–) ions = N.

Number of octahedral void = number of anions

So that the number of octahedral voids = N

Given that

Two out of every three octahedral holes are occupied by ferric ions.

So that the number of ferric (Fe3+) ions = 2N/3

The ratio of the number of Fe3+ ions to the number of O²⁻ ions,

Fe³⁺ : O²⁻ = 2N/3 : N

Multiply 3 and divide by N we get

Fe3+ : O2− = 2 : 3

Hence, the formula of the ferric oxide is Fe2O3.

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Ferric oxide crystallizes in a hexagonal close packed structure of oxide,O​​​​​​2- ions. Two out of every three octohedral holes are occupied by iron ions.what is the formula of ferric oxide?

Ferric oxide crystallizes in a hexagonal close packed structure of oxide,O^2- ions. Two out of every three octohedral holes are occupied by iron ions.what is the formula of ferric oxide?