Question

Ferric oxide crystallizes in an hcp of $O^{2-}$ ions with two out of three octahedral voids (OVs) occupied by $F{e}^{3+}$ ions. The formula of the compound is $F{e}_2{O}_3$.
If true enter 1, else enter 0.

Answer 1

Let the number of $O^{2-}=1$ per atom
Number of OVs $=1$
Number of OVs occupied by $F{e}^{3+}=\frac{2}{3}\times OV=\frac{2}{3}\times 1=\frac{2}{3}$
Formula :$F{e}_{\frac{2}{3}}^{3+}{O}_1^{2-}=F{e}_2{O}_3$