Ferric sulphate, on heating, gives:

S O_{2}

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S O_{3}

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S O_{3}

and

S O_{2}

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none of the above

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Solution

The correct option is C $S O_{3}$ and $S O_{2}$
On heating, ferrous sulphate crystals lose water and anhydrous ferrous sulphate $F e S O_{4}$ is formed. So their colour changes from light green to white. On further heating, anhydrous ferrous sulphate decomposes to form ferric oxide $(F e_{2} O_{3})$ , sulphur dioxide $(S O_{2})$ and sulphur trioxide $(S O_{3}) .$

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Similar questions

S O_{3}

S O_{2} + \frac{1}{2} O_{2}

S O_{3}

1

2 S O_{3} (g) ⇋ 2 S O_{2} (g) + O_{2} (g)

K c

The rates of diffusion of $S O_{2}, C O_{2}, P C l_{3} a n d S O_{3}$ are in the following order –

The heat of formation of $S O_{2}$ is:

$S + \frac{3}{2} O_{2} \to S O_{3} + 2 x k J$
$S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y k J$

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