Question

ferrous chloride and ferric chloride are two chlorides of iron. each of them was prepared from 20 g of iron to get 45.3g of ferrous chloride and 58.04g of ferric chloride. prove that the given information explains the law of multiple proportion

Answer 1

The solution is as follows:


FeCl₂: ratio of Fe : Cl is 1:2

Thus, in 45.3 g of FeCl_​3

$$\begin{gathered} \frac{Fe}{Cl}=\frac{x}{45.3-x} \\ \frac{1}{2}=\frac{x}{45.3-x} \\ 2x=45.3-x \\ 3x=45.3 \\ x=15.1g \\ andinFeC{l}_3: \\ \frac{Fe}{Cl}=\frac{x}{58.04-x} \\ \frac{1}{3}=\frac{x}{58.04-x} \\ x=14.51 \end{gathered}$$

This verifies law of multiple proportions.