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Quantum Number

FeSO4 is a ve...

Question

$F e S O_{4}$ is a very good absorber for $N O$ , the new compound formed by this process is found to contain number of unpaired electrons.

4

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3

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Solution

The correct option is A $3$
$F e S O_{4}$ reacts with NO to form $[F e (H_{2} O)_{5} (N O)]^{2 +}$ . It contains 3 unpaired electrons and has a magnetic moment of 3.89 B.M.
$F e^{2 +} (a q) + N O + S O_{4}^{2 -} (a q) \to [F e (H_{2} O)_{5} (N O)]^{2 +} + S O_{4}^{2 -}$

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