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Standard XII

Chemistry

Oxidation of Alkenes

FeSO4 solutio...

Question

$F e S O_{4}$ solution gives a brown coloured ring during the test for nitrates or nitrites. This due to the formation of:

[F e (H_{2} O)_{5} (N O)]^{2 +}

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[F e (H_{2} O)_{5} (N O_{2})]^{2 +}

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[F e (H_{2} O)_{4} (N O_{2})]^{2 +}

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[F e (H_{2} O)_{4} (N O)]^{2 +}

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Solution

The correct option is A $[F e (H_{2} O)_{5} (N O)]^{2 +}$
$N O_{3}^{-} + 3 F e^{2 +} + 4 H^{+} ⟶ N O + 3 F e^{3 +} + 2 H_{2} O [F e (H_{2} O)_{6}]^{2} + + N O ⟶ [F e (H_{2} O)_{5} N O]^{2 +} + H_{2} O B r o w n r i n g$

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Similar questions

F e {S O}_{4}

is used in brown ring test for nitrates and nitrites In this test, a freshly prepared

F e {S O}_{4}

solution solution is mixed with solution containing

{N O}_{2}^{-}

and

{N O}_{3}^{-}

and the conc,

H_{2} {S O}_{4}

is run down the side of the test tube. If the mixture gets hot or is shaken,

(I)

the brown colour disappear

(I I)

N O

is evolved

(I I I)

a yellow solution of

{F e}_{2} {({S O}_{4})}_{3}

Q. Aqueous solution of

F e S O_{4}

gives tests for both

F e^{2 +}

and

S O_{4}^{2 -}

but after addition of excess of KCN, solution ceases to give test for

F e^{2 +}

. This is due to the formation of :

Q. The complex

[F e (H_{2} O)_{5} N O]^{2 +}

is formed in the brown ring test for nitrates when freshly prepared

F e S O_{4}

solution is added to aqueous solution of

N O_{3}^{-}

followed by addition of

c o n c . H_{2} S O_{4}

. Select correct statement about this complex.

In the given experiment, on heating lead nitrate powder in a boiling test tube, we observe brown fumes. The emission of brown coloured fumes is due to formation of:

Q. In the brown ring test, the brown colour of the ring is due to:

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FeSO4 solution gives a brown coloured ring during the test for nitrates or nitrites. This due to the formation of:

The correct option is A [Fe(H2O)5(NO)]2+NO−3+3Fe2++4H+⟶NO+3Fe3++2H2O[Fe(H2O)6]2++NO⟶[Fe(H2O)5NO]2++H2O Brown ring

$F e S O_{4}$ solution gives a brown coloured ring during the test for nitrates or nitrites. This due to the formation of:

The correct option is A $[F e (H_{2} O)_{5} (N O)]^{2 +}$
$N O_{3}^{-} + 3 F e^{2 +} + 4 H^{+} ⟶ N O + 3 F e^{3 +} + 2 H_{2} O [F e (H_{2} O)_{6}]^{2} + + N O ⟶ [F e (H_{2} O)_{5} N O]^{2 +} + H_{2} O B r o w n r i n g$