Ffind the quotient and remainder of the following pairs. (i) 10,3 (ii) 5,12 (iii) 27,3.
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Solution
(i) When 10 is divided by 3, Quotient is 3 and remainder is 1 as (10=3×3+1) (ii) When 5 is divided by 12, Quotient is 0 and remainder is 12 as (5=12×0+5) (iii) When 27 is divided by 3, Quotient is 9 and remainder is 0 as (27=3×9+0)