Fidnthe coefficient of variation for the following frequency distribution.

$\begin{matrix} Clasees & 0 - 30 & 30 - 60 & 60 - 90 & 90 - 120 & 120 - 150 & 150 - 180 & 180 - 210 Frequency & 2 & 3 & 5 & 10 & 3 & 5 & 2 \end{matrix}$

The sum and sum of squared corresponding to length x (in cm) and weight y (in g) of 50 plant products are given below.
$\sum_{i = 1}^{50} x_{i} = 212, \sum_{i = 1}^{50} x_{i} = x_{i}^{2} = 902.8$ and $\sum_{i = 1}^{50} y_{i} = 261$ , and $\sum_{i = 1}^{50} y_{i}^{2} = 1457.6$

Which is more varying, the length or weight?

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Solution

11.3

or

$(26.4) > (6.6)$

$∴$ Weight is more varying than length because CV(weight) > CV (length)

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Similar questions

The sum and sum of squares corresponding to length x (in cm) and weight y

(in gm) of 50 plant products are given below:

Which is more varying, the length or weight?

The sum and the sum of squares of length x (in cm) and weight y (in g) of 50 plant products are given below:

$\sum_{i = 1}^{50} x_{i} = 212, \sum_{i = 1}^{50} x_{i}^{2} = 902.8, \sum_{i = 1}^{50} y_{i} = 261$ and $\sum_{i = 1}^{50} y_{i}^{2} = 1457.6$

Which is more variable, the length or weight?

X

y

50

50 \sum i = l X_{i} = 212, 50 \sum i = l X_{i}^{2} = 902.8, 50 \sum i = l y_{i} = 261, 50 \sum i = l y_{i}^{2} = 1457.6

x_{1} > 0, i = 1, 2, 3, . . ., 50

50 \sum i = 1 x_{i} = 50

\frac{1}{x_{1}} + \frac{1}{x_{2}} + . . . + \frac{1}{x_{50}}

A . M \geq G M .

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