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Question

Fifty millilitre of a mixture of CO and CH4, was exploded with 85ml of O2. The volume of CO2, produced was 50ml, Calculate the percentage composition of the gaseous mixture.

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Solution

Let the volume of CO =xml
Volume of CH4,=(50x)ml
COxml+12O2x2mlCO2xml ...(i)
CH4(50x)+2O22(50x)CO2(50x)ml+2H2O ...(ii)
Total volume of O2=x2+2(50x)=85
x=10ml
Volume of CO=10ml
Volume of CH4=(5010)=40ml
Percentage of CO=10×10050=20%
Percentage of CH4=(10020)=80%

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