Question

Fifty seeds were selected at random from each of $5$ bags $A,B,C,D,E$ of seeds, and were kept under standardised conditions equally favourable to germination. After $20$ days, the number of seeds which had germinated in each collection were counted and recorded as follow :

Bag	$A$	$B$	$C$	$D$	$E$
Number of seeds germinated	$40$	$48$	$42$	$39$	$41$

What is the probability of germination of

$\left(i\right)$ more than $40$ seeds in a bag?

$\left(ii\right)$ $49$ seeds in a bag?

$\left(iii\right)$ more than $35$ seeds in a bag?

• A. $\left(i\right)0.690$
  $\left(ii\right)0.09$
  $\left(iii\right)1$
• B. $\left(i\right)0.80$
  $\left(ii\right)0.006$
  $\left(iii\right)1$
• C. $\left(i\right)0.70$
  $\left(ii\right)0.001$
  $\left(iii\right)1$
• D. $\left(i\right)0.60$
  $\left(ii\right)0$
  $\left(iii\right)1$

Answer 1

The correct option is D $\left(i\right)0.60$

$\left(ii\right)0$
$\left(iii\right)1$
(i) Number of bags in which more than $40$ seeds out of $50$ seeds germinated $=3$
So, $P$ (more than $40$ seeds in a bag germinated) $=$ $\frac{3}{5}$ $=0.60$
(ii)Number of bags in which $49$ seeds germinated $=0$
So, $P$ ($49$ seeds germinated in bag) $=$ $\frac{0}{5}$ $=0$
(iii) Number of bags in which more than $35$ seeds out $50$ seeds germinated $=5$
Total number of bags$=5$
So, $P$(more than $35$ seeds in a bag germinated) $=$ $\frac{5}{5}$ $=1$