CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Fifty six tuning forks are arranged in a series such that each fork gives 6 beats per second with the preceding one. Assuming the frequency of the last fork to be double of the first fork, the frequency of the last fork should be

A
220 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
330 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
440 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
660 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 660 Hz
From question,
n1+55×6=n2
n+55×6=2n
n=330 Hz
n2=2n
=2×330
=660 Hz.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Periodic Motion and Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon