Question

Fig shown below represents an area $A=0.5m^2$ situated in a uniform magnetic field $B=2.0weber/m^2$ and making an angle of ${60}^o$ with respect to magnetic field. The value of the magnetic flux through the area would be equal to:

• A. $2.0weber$
• B. $\sqrt{3}weber$
• C. $\sqrt{3}/2weber$
• D. $0.5weber$

Answer 1

Answer: (D)

$0.5weber$

$\varphi =B.\left(areanormaltoB\right)=BAcos\theta$

$=2.0\times 0.5\times cos{60}^o$
$=\frac{2.0\times 0.5}{2}=0.5weber$.