Fig, shows a system of four pulleys. The upper two pulleys are fixed and the lower two are movable. What is the velocity ratio of the system?

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Solution

The correct option is D 4
here it is " $4$ " pulley system,if effort will move at distance " $d$ " then load will move at distance " $\frac{d}{n}$ "
hence velocity ration( $V . R$ )= $\frac{d}{d / 4}$ =4
where " $n$ "=number of pulley

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Fig, shows a system of four pulleys. The upper two pulleys are fixed and the lower two are movable. What is the velocity ratio of the system?

The correct option is D 4here it is "4" pulley system,if effort will move at distance "d" then load will move at distance "dn"hence velocity ration(V.R)=dd/4=4where "n"=number of pulley

The correct option is D 4
here it is " $4$ " pulley system,if effort will move at distance " $d$ " then load will move at distance " $\frac{d}{n}$ "
hence velocity ration( $V . R$ )= $\frac{d}{d / 4}$ =4
where " $n$ "=number of pulley