Fig., shows a uniform metre scale of weight $W$ supported on a fulcrum at the $60 c m$ mark by applying the effort $E$ at the $90 c m$ mark. What is the mechanical advantage in an ideal case ?

3

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Solution

The correct option is D $3$
The mechanical advantage of a lever is the ratio of the length of the lever on the applied force side of the fulcrum to the length of the lever on the resistance force side of the fulcrum. That is, $M A = \frac{d i s t a n c e c o v e r e d b y e f f o r t a r m}{d i s t a n c e c o v e r e d b y l o a d a r m}$ .
The distance between the fulcrum and the input force is known as the load arm. The distance from the fulcrum to the output force is known as the effort arm.
In this case, The fulcrum is at $60 c m$ and the load that is, the weight of the $1 m$ scale acts at its center, that is, at $50 c m$ . Hence, the load arm distance is $10 c m$ and the effort arm distance is $30 c m$ .
Therefore, the mechanical advantage in this case is given as follows.
$M A = \frac{30 c m}{10 c m} = 3$ .
Hence, the mechanical advantage in ideal case is 3.

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Fig., shows a uniform metre scale of weight W supported on a fulcrum at the 60cm mark by applying the effort E at the 90cm mark. What is the mechanical advantage in an ideal case ?

Fig., shows a uniform metre scale of weight $W$ supported on a fulcrum at the $60 c m$ mark by applying the effort $E$ at the $90 c m$ mark. What is the mechanical advantage in an ideal case ?