Figure (16-E111)shows a person standing somehere in between two identical tuning forks, each vibrating at

512 Hz. If both the tuning forks move towards right at a speed of 5.5 m s^{-1}, find the number of beats heard by the listener. Speed of sound in air = $330 m s^{- 1}$ .

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Solution

According to the data,

$V_{s} = 5.5$ m/s for each tuning fork So, the apparent frequency heard from the tuning fork on the left,

$f^{1} = (\frac{330}{330 - 5.5}) \times 512$

=520.68 Hz

Similarly, apparent frequency from the tuning fork on the right

$f^{11} = (\frac{330}{330 - 5.5}) \times 512$

=503.60 Hz

So, beats produced

=520.68-503.60=17.5 Hz

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Similar questions

Q. Figure shows a person standing somewhere in between two identical tuning forks. each vibrating at 512 Hz. If both the tuning forks move towards right a speed of 5.5 m s⁻¹, find the number of beats heard by the listener. Speed of sound in air = 330 m s⁻¹.

Q. Two identical tuning forks vibrating at the same frequency 256 Hz are kept fixed at some distance apart. A listener runs between the forks at a speed of 3.0m s⁻¹ so that he approaches one tuning fork and recedes from the other figure. Find the beat frequency observed by the listener. Speed of sound in air = 332 m s⁻¹.

Two identical tuning forks vibrating at the same frequency 256 Hz are kept fixed at some distance apart. A listener runs between the forks at a speed of 3.0 m/s so that he approaches one tuning fork and recedes from the other (figure 16-E10). Find the beat frequency observed by the listener. Speed of sound in air = 332 m/s.

Q. Two identical tuning forks vibrating at the same frequency

256 H z

are kept fixed at some distance apart. A listener runs between the forks at a speed of

3.0 m / s

so that the approaches one tuning fork and recedes from the other figure. Then the beat frequency observed by the listener. Speed of sound in air

= 332 m / s

Two identical tuning forks vibrating at the same frequency 256 Hz are kept fixed at some distance apart. A listener runs between the forks at a speed of 3.0 m/s so that he approaches one tuning fork while receding from the other (figure). Find the beat frequency observed by the listener. Speed of sound in air = 332 m/s.

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Figure (16-E111)shows a person standing somehere in between two identical tuning forks, each vibrating at 512 Hz. If both the tuning forks move towards right at a speed of 5.5 m s^{-1}, find the number of beats heard by the listener. Speed of sound in air =330ms−1.

According to the data, Vs=5.5 m/s for each tuning fork So, the apparent frequency heard from the tuning fork on the left, f1=(330330−5.5)×512 =520.68 Hz Similarly, apparent frequency from the tuning fork on the right f11=(330330−5.5)×512 =503.60 Hz So, beats produced =520.68-503.60=17.5 Hz

Figure (16-E111)shows a person standing somehere in between two identical tuning forks, each vibrating at

512 Hz. If both the tuning forks move towards right at a speed of 5.5 m s^{-1}, find the number of beats heard by the listener. Speed of sound in air = $330 m s^{- 1}$ .