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Question

Figure (32.E2) shows an arrangement to measure the emf ϵ and internal resistance r of a battery. The voltmeter has a very high resistance and the ammeter also has some resistance. The voltmeter reads 1.52 V when the switch S is open. When the switch is closed the voltmeter reading drops to 1.45 V and the ammeter reads 1.0 A. Find the emf and the internal resistance of the battery.

Figure (32.E2)

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Solution

When switch is open no current pass through the ammeter in the upper part of the circuit as the voltmeter has resistant. Thus current in it is zero. Voltmeter reads the emf (there is no potential drop across the register), (b) When switch is closed current passes through the circuit the value of l The voltmeter reads ϵiR=1.45 1.52iR=1.45 iR=0.07 1.R=0.07


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